Jachdo wrote: Leaving the 3* characters out, we have twelve 2* heroes. 10 of these heroes have 3 unique covers each, and two have 2 unique covers each -- that's 34 potential covers that could drop. If my math is correct (and it may very well not be), the chances of pulling the same Blue Hawkeye 10x is... very, very unlikely. 10 drawn from a pool of 34 gives up approximately 131,000,000 combinations. C(n,r) n= 34 (total covers) r= 10 (number of samples) 34!/(10!(34-10)!) = 131,128,140 On reflection, the total number of permutations is actually smaller since that sample was pulled from a smaller pool of 2* characters. Regardless, it's damn unlikey